باستخدام
العلامة الزائية Z:
القوانين المستخدمة هنا
هي: S2 =
[ ∑ (xi –`X
)2]
/ n حيث S
الانحراف المعياري أو
σ ،
كما أنَّ
S2 مقدار التباين
Zx
= (X
–`X)
÷
Sx ,
Zy
= (Y–`Y
) ÷
Sy
,
r =
[∑( Zx
Zy)] / n
|
X |
Y |
X
–`X |
Y–`Y
|
(X
–`X)2 |
Zx |
(Y–`Y)2 |
Zy |
Zx
Zy |
|
6 |
4 |
– 3.444 |
– 3.889 |
11.861 |
– 1.430*** |
15.124 |
–1.975*** |
2.824 |
|
8 |
8 |
– 1.444 |
0.111 |
2.085 |
– 0.599 |
0.012 |
0.056 |
– 0.034 |
|
7 |
6 |
– 2.444 |
– 1.889 |
5.973 |
– 1.015 |
3.568 |
– 0.959 |
0.973 |
|
14 |
10 |
4.556 |
2.111 |
20.757 |
1.891 |
4.456 |
1.072 |
2.028 |
|
11 |
9 |
1.556 |
1.111 |
2.421 |
0.646 |
1.234 |
0.564 |
0.364 |
|
12 |
11 |
2.556 |
3.111 |
6.533 |
1.061 |
9.678 |
1.580 |
1.676 |
|
8 |
8 |
– 1.444 |
0.111 |
2.085 |
– 0.599 |
0.012 |
0.056 |
– 0.034 |
|
9 |
7 |
– 0.444 |
– 0.889 |
0.197 |
– 0.184 |
0.790 |
– 0.451 |
0.083 |
|
10 |
8 |
0.556 |
0.111 |
0.309 |
0.231 |
0.012 |
0.056 |
0.013 |
|
85 |
71 |
0.004 |
– 0.001 |
52.222 |
0.002 |
34.889 |
– 0.001 |
7.894 |
|
`X
= 85
÷ 9
=
9.444 |
`Y
= 71 ÷ 9
= 7.889 |
|
∑(X
–`X)2
÷ 9
= 5.802 |
|
∑(Y–`Y)2
÷ 9
= 3.877 |
r = 7.894
÷ 9
= 0.877 |
|
Sx= σ
=
2.409 |
Sy
= σ =1.969
|
|
***
– 3.444
÷ 2.409 =
– 1.430
, ***
– 3.889
÷ 1.969
=
–1.975